x^2+6,84^2=20^2

Solution for x^2+6,84^2=20^2 equation:

x^2+6.84^2=20^2

We move all terms to the left:

x^2+6.84^2-(20^2)=0

We add all the numbers together, and all the variables

x^2-353.2144=0

a = 1; b = 0; c = -353.2144;
Δ = b2-4ac
Δ = 02-4·1·(-353.2144)
Δ = 1412.8576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1412.8576}}{2*1}=\frac{0-\sqrt{1412.8576}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1412.8576}}{2*1}=\frac{0+\sqrt{1412.8576}}{2}
=\frac{\sqrt{}}{2}
$